Eureka Math Grade 4 Module 1 Lesson 16 Answer Key (2024)

Table of Contents

Engage NY Eureka Math 4th Grade Module 1 Lesson 16 Answer Key Eureka Math Grade 4 Module 1 Lesson 16 Sprint Answer Key Eureka Math Grade 4 Module 1 Lesson 16 Problem Set Answer Key Eureka Math Grade 4 Module 1 Lesson 16 Exit Ticket Answer Key Eureka Math Grade 4 Module 1 Lesson 16 Homework Answer Key FAQs References

Engage NY Eureka Math 4th Grade Module 1 Lesson 16 Answer Key

Eureka Math Grade 4 Module 1 Lesson 16 Sprint Answer Key

A
Convert Meters and Centimeters to Centimeters

Explanation:
1 meter = 100 Centimeter
Toconvert from meters to centimeters, simply multiply the number ofmetersby 100 and change the units tocm.

Question 1.
2 m = cm
Answer:
2 m = 2× 100 cm = 200 cm.

Question 2.
3 m = cm
Answer:
3 m = 3× 100 cm = 300 cm.

Question 3.
4 m = cm
Answer:
4 m = 4 × 100 cm = 400 cm.

Question 4.
9 m = cm
Answer:
9 m = 9 × 100 = 900 cm.

Question 5.
1 m = cm
Answer:
1 m = 1×100 = 100 cm.

Question 6.
7 m = cm
Answer:
7 m = 7 × 100 = 700 cm.

Question 7.
5 m = cm
Answer:
5 m = 5×100 = 500 cm.

Question 8.
8 m = cm
Answer:
8 m = 8×100 = 800 cm.

Question 9.
6 m = cm
Answer:
6 m = 6×100 = 600 cm.

Question 10.
1 m 20 cm = cm
Answer:
1 m 20 cm = 1×100 cm 20 cm =100 cm 20 cm = 120 cm.

Question 11.
1 m 30 cm = cm
Answer:
1 m 30 cm = 1×100 cm 30 cm = 100 cm 30 cm = 130 cm.

Question 12.
1 m 40 cm = cm
Answer:
1 m 40 cm = 1×100 cm 40 cm = 100 cm 40 cm = 140 cm.

Question 13.
1 m 90 cm = cm
Answer:
1 m 90 cm = 1×100 cm 90 cm = 100 cm 90 cm = 190 cm.

Question 14.
1 m 95 cm = cm
Answer:
1 m 95 cm = 1×100 cm 95 cm = 195 cm.

Question 15.
1 m 85 cm = cm
Answer:
1 m 85 cm = 1×100 cm 85 cm =185 cm.

Question 16.
1 m 84 cm = cm
Answer:
1 m 84 cm = 1×100 cm 84 cm = 184 cm.

Question 17.
1 m 73 cm = cm
Answer:
1 m 73 cm = 1×100 cm 73 cm = 173 cm.

Question 18.
1 m 62 cm = cm
Answer:
1 m 62 cm = 1×100 cm 62 cm = 162 cm.

Question 19.
2 m 62 cm = cm
Answer:
2 m 62 cm = 2× 100 cm 62 cm = 262 cm.

Question 20.
7 m 62 cm = cm
Answer:
7 m 62 cm = 7×100 cm 62 cm = 762 cm.

Question 21.
5 m 27 cm = cm
Answer:
5 m 27 cm = 5× 100 cm 27 cm =527 cm.

Question 22.
3 m 87 cm = cm
Answer:
3 m 87 cm = 3×100 cm 87 cm = 387 cm.

Question 23.
1 m 2 cm = cm
Answer:
1 m 2 cm = 1×100 cm 2 cm = 102 cm.

Question 24.
1 m 3 cm = cm
Answer:
1 m 3 cm = 1×100 cm 3 cm = 103 cm.

Eureka Math Grade 4 Module 1 Lesson 16 Problem Set Answer Key

Estimate first, and then solve each problem. Model the problem with a tape diagram. Explain if your answer is reasonable.

Question 1.
On Monday, a farmer sold 25,196 pounds of potatoes. On Tuesday, he sold 18,023 pounds. On Wednesday, he sold some more potatoes. In all, he sold 62,409 pounds of potatoes.
Answer:
Number of pounds of potatoes sold on Monday = 25,196 pounds
Number of pounds of potatoes sold on Tuesday = 18,023 pounds
Number of pounds of potatoes sold on Wednesday = X pounds.
Total number of pounds of potatoes a farmer sold all together = 62,409 pounds.
a. About how many pounds of potatoes did the farmer sell on Wednesday? Estimate by rounding each value to the nearest thousand, and then compute.
Answer:

b. Find the precise number of pounds of potatoes sold on Wednesday.
Answer:

c. Is your precise answer reasonable? Compare your estimate from (a) to your answer from (b). Write a sentence to explain your reasoning.
Answer:
Yes, my precise answer is reasonable. On rounding to the nearest thousand answer is 19,000 and my precise value is 19,386 . Both the values are close enough.

Question 2.
A gas station had two pumps. Pump A dispensed 241,752 gallons. Pump B dispensed 113,916 more gallons than Pump A.
Answer:
Given:
Number of gallons of gas pumped by Pump A = 241,752 gallons
Number of gallons of gas pumped by Pump B = 113,916 more gallons than Pump A

a. About how many gallons did both pumps dispense? Estimate by rounding each value to the nearest hundred thousand and then compute.
Answer:

b. Exactly how many gallons did both pumps dispense?
Answer:

c. Assess the reasonableness of your answer in (b). Use your estimate from (a) to explain.
Answer:
The Exact and the Estimation Answers are so close to each other. The difference between them is
600,000 – 597,420 = 2,580 which is not a huge difference.

Question 3.
Martin’s car had 86,456 miles on it. Of that distance, Martin’s wife drove 24,901 miles, and his son drove 7,997 miles. Martin drove the rest.
Given:
Total distance reading on Martin’s car = 86,456 miles
From that Martin’s wife drove = 24,901 miles.
From that Martin’s son drove =7, 997 miles.
Remaining drove by Martin = 86,456 – 24,901 – 7,997
a. About how many miles did Martin drive? Round each value to estimate.
Answer:

b. Exactly how many miles did Martin drive?
Answer:

c. Assess the reasonableness of your answer in (b). Use your estimate from (a) to explain.
Answer:
Both the answer are relatively close. They both are reasonable answers.

Question 4.
A class read 3,452 pages the first week and 4,090 more pages in the second week than in the first week. How many pages had they read by the end of the second week? Is your answer reasonable? Explain how you know using estimation.
Answer:
Number of pages read by A class in the first week = 3,452 pages
Number of pages read by the class in the second week = 4,090 more than week 1 = 4,090 + 3,452

Question 5.
A cargo plane weighed 500,000 pounds. After the first load was taken off, the airplane weighed 437,981 pounds. Then 16,478 more pounds were taken off. What was the total number of pounds of cargo removed from the plane? Is your answer reasonable? Explain.
Answer:
Total weight of a cargo plane = 500,000 pounds
After the first load the weight of the plane = 437,981 pounds
Again a load of weight was taken off the plane = 16,478
The total number of pounds of cargo removed from the plane =

Eureka Math Grade 4 Module 1 Lesson 16 Exit Ticket Answer Key

Quarterback Brett Favre passed for 71,838 yards between the years 1991 and 2011. His all-time high was 4,413 passing yards in one year. In his second highest year, he threw 4,212 passing yards.
Answer:
Given:
Total yards passed = 71,838
The passing yard in one year = 4,413
The passing yard in the second year = 4,212

Question 1.
About how many passing yards did he throw in the remaining years? Estimate by rounding each value to the nearest thousand and then compute.
Answer:

Question 2.
Exactly how many passing yards did he throw in the remaining years?
Answer:

Question 3.
Assess the reasonableness of your answer in (b). Use your estimate from (a) to explain.
Answer:
The answer in (b) is 63,213 .and the estimated answer is 64,000. Both the answers are close and reasonable.

Eureka Math Grade 4 Module 1 Lesson 16 Homework Answer Key

Question 1.
Zachary’s final project for a college course took a semester to write and had 95,234 words. Zachary wrote 35,295 words the first month and 19,240 words the second month.
Given:
Total words written in the Zachary’s final project in the complete semester = 95,234 words
Number of words Zachary’s wrote in the first month = 35,295 words
Number of words Zachary’s wrote in the second month = 19,240 words
a. Round each value to the nearest ten thousand to estimate how many words Zachary wrote during the remaining part of the semester.
Answer:

b. Find the exact number of words written during the remaining part of the semester.
Answer:

c. Use your answer from (a) to explain why your answer in (b) is reasonable.
Answer:
Yes, my answer is reasonable because 40,699 is estimated to 40,000 on rounding to nearest ten thousand.

Question 2.
During the first quarter of the year, 351,875 people downloaded an app for their smartphones. During the second quarter of the year, 101,949 fewer people downloaded the app than during the first quarter. How many downloads occurred during the two quarters of the year?
GIVEN:
Number of people downloaded an app during the first quarter of the year = 351,875
Number of people downloaded an app during the second quarter of the year = 351,875 -101,949
a. Round each number to the nearest hundred thousand to estimate how many downloads occurred during the first two quarters of the year.
Answer:

b. Determine exactly how many downloads occurred during the first two quarters of the year.
Answer:

c. Determine if your answer is reasonable. Explain.
Answer:
Yes, my answer is reasonable as 700,000 is the next highest hundred thousand number to 601,801.

Question 3.
A local store was having a two-week Back to School sale. They started the sale with 36,390 notebooks. During the first week of the sale, 7,424 notebooks were sold. During the second week of the sale, 8,967 notebooks were sold. How many notebooks were left at the end of the two weeks? Is your answer reasonable?
Answer:
The local store started the sale = 36,390 books
number of books sold during the first week =7,424 notebooks
Number of books sold during the second week = 8,967 notebooks.

Eureka Math Grade 4 Module 1 Lesson 16 Answer Key (2024)

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